Question

Subtract 3x2 – 5y – 2 from 5y – 3x2 + xy and find the value of the result if x = 2; y = 1

Answer 1

Answer:

$= > 5y - 3x² + xy - 3x² - 5y - 2$

$= > 5y - 5y - 3x² - 3x² + xy - 2$

$= > { - 6x}^{2} + xy - 2$

Now , put the value

• x = 2

• y = 1

$= > { - 6x}^{2} + xy - 2$

$= > - 6 \times 2 × -6 × 2 + 2 \times 1 - 2$

=> -12 × (-12) + 2 - 2

=> 12 × 12 +2 -2

=> 144

Answer 2

SOLUTION

TO DETERMINE

1. To subtract : 3x² – 5y – 2 from 5y – 3x² + xy

2. Find the value of the result fot x = 2 , y = 1

EVALUATION

1. Here the given expressions are

3x² – 5y – 2 and 5y – 3x² + xy

On subtraction we get

= ( 5y – 3x² + xy ) - ( 3x² – 5y – 2 )

= 5y – 3x² + xy - 3x² + 5y + 2

= - 6x² + xy + 10y + 2

2. Putting x = 2 , y = 1 we get

The required result

$\sf{ = - 6 {x}^{2} + xy + 10y + 2 }$

$\sf{ = - 6 \times {(2)}^{2} + (2 \times 1) + (10 \times 1) + 2 }$

$\sf{ = - 24 + 2 + 10+ 2 }$

$\sf{ = - 10 }$

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