Math, asked by vs1696218, 3 months ago

Subtract 3x²+5y²-2z² from the sum of 5y²+3z² and 2x²-3y²​

Answers

Answered by SamVarghese
0

sum of 5y²+3z² and 2x²-3y²

5y²+3z² + 2x²-3y²

= 2x² + 5y² - 3y² + 3z²

= 2x² + 2y² + 3z²

(2x² + 2y² + 3z²) - (3x²+5y²-2z²)

2x² + 2y² + 3z² - 3x² - 5y² + 2z²

2x² -3x² +2y² -5y² + 3z² +2z²

-x² -3y² +5z²

Answered by sandeep4522
0

Answer:

I hope it's help you

thank you

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