Question

subtract 4c(-a+4b+c) from 3a(a+b+c)-5b(a-b+c)​

Answer 1

Answer:3a²+5b²-4c²+7a-21bc-2ab

Answer 2

Answer: 3a^2+8ab+7ac+5b^2-11bc+4c^2

Step-by-step explanation:

First let's start with 3a(a+b+c)-5b(a-b+c)

(i) L.H.S= 3a(a+b+c)

           = 3a^2+3ab+3ac

  R.H.S=-5b(a-b+c)

           = -5ba-5b^2-5bc

Now let's substitute,

=(3a^2+3ab+3ac)-(-5ba-5b^2-5bc)

Now let's take the like terms together,

=3a^2+3ab+5ab+3ac+5b^2+5bc

=3a^2+8ab+3ac+5b^2+5bc

Now let's subtract 4c(-a+4b+c) with 3a^2+8ab+3ac+5b^2+5bc

(ii) First let's open the bracket of 4c(-a+4b+c)

   = -4ca+16bc+4c^2

Now let's subtract eq (ii) from (i)

=( 3a^2+8ab+3ac+5b^2+5bc)-(-4ca+16bc+4c^2)

=3a^2+8ab+3ac+4ac+5b^2+5bc-16bc+4c^2

=3a^2+8ab+7ac+5b^2-11bc+4c^2 (Final answer)

I hope you understood...