Question

Subtract 4x - 2y + z from the sum of 3x + 4y + z and - 6x + 7y - 8z.
Subtract the sum of 2x2 - 4x + 11 and 7x2 - 4x + 1 from the sum of 8x2 - 7x - 7 and
6x + 4x - 6.
Subtract the sum of 4721-3812 +4 and - 3721-7712_7 from 12 + 4​

Answer 1

1. {(3x+4y+z)+(-6x+7y-8z)} - (4x-2y+z)

=(3x+4y+z-6x+7y-8z)-(4x-2y+z)

=(3x-6x+4y+7y+z-8z)-(4x-2y+z)

=(-3x+11y-7z)-(4x-2y+z)

=-3x+11y-7z-4x+2y-z

=-3x-4x+11y+2y-7z-z

=-7x+13y-8z(Ans)

3.(12+4)-{(4721-3812+4)+(-3721-7712-7)}

=16-(913-11440)

=16-(-10527)

=16+10527

=10543(Ans)