Subtract 4y(2x+y+z) from 3x(x+y-z)..........plz don't spam and solve with full step
Answers
Answered by
1
Step-by-step explanation:
3x(x+y-z) - 4y(2x+y+z)
= 3x^2+3xy-3xz-8xy-4y^2-4yz
= 3x^2+3xy-8xy-3xz-4y^2-4yz
= 3x^2-5xy-3xz-4y^2-4yz
= 3x^2-3xz-4y^2-4yz-5xy (Ans)
Answered by
0
Answer:
Step-by-step explanation:
3x(x+y-z) - 4y(2x+y+z)
= 3x^2+3xy-3xz-8xy-4y^2-4yz
= 3x^2+3xy-8xy-3xz-4y^2-4yz
= 3x^2-5xy-3xz-4y^2-4yz
= 3x^2-3xz-4y^2-4yz-5xy (Ans)
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