Math, asked by samanvithareddyjukan, 8 months ago

Subtract 6a2 - 12ab - 15ac from 18a2 -12ac - 30bc.

Answers

Answered by Soham2020
1

Answer:

Correct answer -

( 18a2 - 12ac - 30bc ) - ( 6a2 - 12ab - 15ac )

18a2 - 12ac - 30bc - 6a2 + 12ab + 15ac

18a2 - 6a2 - 12ac + 15ac - 30bc - 12ab

12a2 - 27ac - 30bc - 12ab

Answered by satishbgite
0
(18a^2-12ac-30bc) - (6a^2 - 12ab - 15ac)
=18a^2 - 12ac - 30bc - 6a^2 + 12ab + 15ac
= 18a^2 - 6a^2 - 12ac +15ac -30bc - 12ab
= 12a^2 + 3ac - 30bc - 12ab

Hope it helps
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