Physics, asked by Dheerajkhemani7842, 1 year ago

Two trains a and b of length 400m each are moving on two parallel tracks with a uniform speed of 72 km per hour in the same direction with a ahead of p the driver of weedicides overtake a and accelerates by one metre per second square if after 50 second the god of be just dresses pass the driver of a what was the original distance between them

Answers

Answered by amitnrw
101

Answer:

450 m

Explanation:

Speed of  Train a = 72 km/hr = 72 * 5/18 = 20 m/s

Distance covered by Train a in 50 sec

= 50*20 = 1000m

Speed of Train b = 20 m/s

acceleration = 1 m/s²

Distance Covered in 50 sec

= 20*50  + (1/2)*1*50²

= 1000 + 1250

Extra Distance Covered by Train b = 1250 m

Length of both trains = 400 + 400 = 800 m

the original distance between them = 1250 - 800 = 450 m

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