Math, asked by poojadasgupta15, 3 days ago

Subtract (7b-3a + 8) from the sum of (2a + 4b-c+1) and (3b-5a +9c).​

Answers

Answered by queenofdevils177
0

Answer:

(2a+4b-c+1). + (3b-5a+9c) - (7b-3a+8)

Step-by-step explanation:

2a + 4b -c+1 + 3b -5a +9c - (7b - 3a + 8)

2a-5a +4b+3b -c+9c +1 -(7b -3a +8 )

-3a + 7b +8c +1 -(7b - 3a +8 )

-3a + 7b + 8c + 1 -7b + 3a - 8

-3a + 3a + 7b + 7b +1 - 8 +8c

14b - 7 + 8c

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