subtract (8a–6a+9) and (–10a–8+8a2)
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Answer:
−3−[(8a−6a
2
+9)+(−10a−8+8a
2
)]
=−3−[8a−6a
2
+9+−10a−8+8a
2
]
=−3−[(8a−10a)+(−6a
2
+8a
2
)+(9−8)]
=−3−[−2a+2a
2
+1]
=−3+2a−2a
2
−1
=+2a−2a
2
−4
=−2a
2
+2a−4
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