Question

subtract a3-3a2 from b3-3b3

Answer 1

b³-3b²

a³-3a²

- +

b³-a³+ 3(a² -b²)

Answer 2

Question:

subtract a3-3a2 from b3-3b3

Answer:

b³-3b²  - a³-3a²

= $b^{3} - a^3 - 3b^2 - 3a^2$

Factorizing -3b2 - 3a2

= $b^3 - a^3 - 3(b^2 - a^2)$

So, the answer is  $b^3 - a^3 - 3(b^2 - a^2)$

M a r k   B r a i n l i e s t   i f   h e l p e d ! !

Tq dear frnd!!