Math, asked by PRIME11111, 1 year ago

Subtract a⁴+a³+a²+6a-3from the sum of 7+6a⁴-4a-7a³and -a⁴+a-3​

Answers

Answered by lipimohapatra01
28

The sum of 7+6a⁴-4a-7a³ and-a⁴+a-3

=(6a⁴-7a³-4a+7)+(-a⁴+a-3)

=6a⁴-7a³-4a+7-a⁴+a-3

=6a⁴-a⁴-7a³-4a+a+7-3

=5a⁴-7a³-3a+4

Subtracted a⁴+a³+a² +6a-3 from the sum(5a⁴-7a³-3a+4)

=(5a⁴-7a³-3a+4)-(a⁴+a³+a²+6a-3)

=5a⁴-7a³-3a+4-a⁴-a³-a²-6a+3

=5a⁴-a⁴-7a³-a³-a²-3a-6a+4+3

=4a⁴-8a³-a²-9a+7 (Ans)

Answered by ajitboraik659
6

Step-by-step explanation:

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