Subtract the second expression from the first:(5x+4y+7z);(x+2y+3z) 2) Simplify the following expression: 140÷[(-11)×(-3)-(-42)÷14-1 3) Subtraction: 7/11-3/7
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Given First expression is x+2y+z
Second expression is −x−y−3z
Subtracting second expression from first one will give
=x+2y+z−(−x−y−3z)
=x+2y+z+x+y+3z
=2x+3y+4z
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