subtract the seeord pholenomial and find the degree of the resultant pholenomial . p (x) = 7 x^2 + 6x - 1 , q (x) = 6x -9
Answers
Answered by
0
Answer:
426(41(-_#!-+stjyxgj
Answered by
0
Given : p (x) = 7 x² + 6x - 1 , q (x) = 6x -9
subtract q (x) from p (x)
To Find : the degree of the resultant polynomial
Solution:
p (x) = 7 x² + 6x - 1
q (x) = 6x -9
subtract q (x) from p (x)
p(x) - q(x)
= 7 x² + 6x - 1 - (6x - 9)
= 7 x² +8
resultant polynomial is 7 x² +8
Highest power is 2
Hence degree of the resultant polynomial 7 x² +8 is 2
Degree is 2
Learn More:
on dividing x3-3x2+x+2 by a polynomial g(x),the quotient and ...
brainly.in/question/3135153
Divide 9x^3+3x^2-5x+7 by (3x-1) write the quotient and remainder ...
brainly.in/question/6190809
Divide the polynomial (6x³ + 11x² - 10x - 7) by the binomial (2x + 1 ...
brainly.in/question/4743553
Similar questions