Question

Subtract the sum 3x2-4y2+5xy+20 to obtain –x-Y+6xy+20?​

Answer 1

Answer: Let q should be subtracted.

Then according to question,

3x2−4y2+5xy+20−q=−x2−y2+6xy+20

⇒q=3x2−4y2+5xy+20−(−x2−y2+6xy+20)

⇒q=3x2−4y2+5xy+20+x2+y2−6xy−20

⇒q=3x2+x2−4y2+y2+5xy−6xy+20−20

⇒q=4x2−3y2−xy+0

Hence, 4x2−3y2−xy should be subtracted

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