Question

Subtract the sum of 12ab –10bc –18ac and 9ab + 12bc + 14ac from the sum of
ab + 2bc and 3bc – ac.

Answer 1

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Answer 2

we have to subtract the sum of 12ab - 10bc - 18ac and 9ab + 12bc + 14ac from the sum of ab + 2bc and 3bc - ac.

solution : step 1 : find the sum of 12ab - 10bc - 18ac and 9ab + 12bc + 14ac.

(12ab - 10bc - 18ac) + (9ab + 12bc + 14ac)

= (12 + 9)ab + (-10 + 12)bc + (-18 + 14)ac

= 21ab + 2bc + (-4)ac

= 21ab + 2bc - 4ac

step 2 : find the sum of ab + 2bc and 3bc - ac.

(ab + 2bc) + (3bc - ac)

= ab + (2 + 3)bc - ac

= ab + 5bc - ac

step 3 : subtract 21ab + 2bc - 4ac from ab + 5bc - ac.

= (ab + 5bc - ac) - (21ab + 2bc - 4ac)

= (1 - 21)ab + (5 - 2)bc + (-1 + 4)ac

= -20ab + 3bc + 3ac

Therefore the answer is -20ab + 3bc + 3ac