Subtract the sum of 12ab –10bc –18ac and 9ab + 12bc + 14ac from the sum of
ab + 2bc and 3bc – ac.
Answers
Answered by
0
hope it help u
mark me Branilest
Attachments:
Answered by
4
we have to subtract the sum of 12ab - 10bc - 18ac and 9ab + 12bc + 14ac from the sum of ab + 2bc and 3bc - ac.
solution : step 1 : find the sum of 12ab - 10bc - 18ac and 9ab + 12bc + 14ac.
(12ab - 10bc - 18ac) + (9ab + 12bc + 14ac)
= (12 + 9)ab + (-10 + 12)bc + (-18 + 14)ac
= 21ab + 2bc + (-4)ac
= 21ab + 2bc - 4ac
step 2 : find the sum of ab + 2bc and 3bc - ac.
(ab + 2bc) + (3bc - ac)
= ab + (2 + 3)bc - ac
= ab + 5bc - ac
step 3 : subtract 21ab + 2bc - 4ac from ab + 5bc - ac.
= (ab + 5bc - ac) - (21ab + 2bc - 4ac)
= (1 - 21)ab + (5 - 2)bc + (-1 + 4)ac
= -20ab + 3bc + 3ac
Therefore the answer is -20ab + 3bc + 3ac
Similar questions