Question

subtract the sum of 13x-4y+7z and -6z+6x+3y from the sum of 6x-4y-4z and 2x+4y-7z.

Answer 1

$\mathfrak{\large{\underline{\underline{Answer :-}}}}$

The answer is - 11x - 12z + y

$\mathfrak{\large{\underline{\underline{Explanation :-}}}}$

Given :

Sum of 13x - 4y + 7z and -6z + 6x + 3y subtracted from sum of 6x - 4y - 4z and 2x + 4y - 7z

To Find :

The Difference of the sum of the given values

Solution :

★ Sum of 13x - 4y + 7z and -6z + 6x + 3y

$\implies$ 13x - 4y + 7z + (- 6z + 6x + 3y)

$\implies$ 13x + 6x - 4y + 3y + 7z - 6z

$\implies$ 19x - y + z

$\rule{300}{1.5}$

★ Sum of 6x - 4y - 4z and 2x + 4y - 7z

$\implies$ 6x - 4y - 4z + (2x + 4y - 7z)

$\implies$ 6x + 2x - 4y + 4y - 4z - 7z

$\implies$ 8x - 0 - 11z

$\implies$ 8x - 11z

$\rule{300}{1.5}$

★ Subtraction of 8x - 11z & 19x - y + z

$\implies$ 8x - 11z - (19x - y + z)

$\implies$8x - 11z - 19x + y - z

$\implies$ 8x - 19x - 11z - z + y

$\implies$ - 11x - 12z + y

$\therefore$ The answer is - 11x - 12z + y