Divide 2x³+3x²+5x+6 by x²+3x+2. Find the quotient and remainder and verify the division algorithm
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After dividing 2x^3 + 3x^2 + 5x + 6 from x^2 + 3x + 2
we will get
dividend -> x^2 + 3x + 2
divisor -> 2x^3 + 3x^2 + 5x + 6
remainder -> 10x + 12
quotient -> 2x - 3
to verify division algorithm :-
2x^3 + 3x^2 + 5x + 6 = ( x^2 + 3x + 2) (2x -3) × 10x + 12
solving RHS
( x^2 + 3x + 2) (2x -3) × 10x + 12
=2x^3 + 6x^2 + 4x - 3x^2 - 9x - 6 + 10x + 12
= 2x^3 + 3x^2 + 5x + 6
here, LHS = RHS
hence verified
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