Question

Subtract the sum of -19/18 and -11/12 from the difference of -1/3 and 1/2​

Answer 1

Answer:

• Required answer: 101/36

Step-by-step explanation:

To subtract:

• The sum of -19/18 and -11/12 from the difference of -1/3 and 1/2.

Finding the sum of -19/18 and -11/12:

• Sum = -19/18 + -11/12
• Sum = (-19 × 2)/(18 × 2) + (-11 × 3)/(12 × 3)
• Sum = -38/36 + -33/36
• Sum = -71/36

Finding the difference of -1/3 and 1/2:

• Difference = 1/2 - (-1/3)
• Difference = 1/2 + 1/3
• Difference = (1 × 3)/(2 × 3) + (1 × 2)/(3 × 2)
• Difference = 3/6 + 2/6
• Difference = 5/6

Subtracting the sum of -19/18 and -11/12 from the difference of -1/3 and 1/2:

• The sum of -19/18 and -11/12 = -71/36
• The difference of -1/3 and 1/2 = 5/6

Subtracting -71/36 from 5/6.

• Subtract = 5/6 - (-71/36)
• Subtract = 5/6 + 71/36
• Subtract = (5 × 6)/(6 × 6) + 71/36
• Subtract = 30/36 + 71/36
• Subtract = 101/36

∴ Subtracting the sum of -19/18 and -11/12 from the difference of -1/3 and 1/2, we get 101/36.

Answer 2

Q.

Subtract the sum of -19/18 and -11/12 from the difference of -1/3 and 1/2

Solution :

First

The sum of -19/18 and -11/12

= (-19/18) + (-11/12)

= -19/18 - 11/12

= (-38 -33)/36

= -71/36

And

The difference of -1/3 and 1/2

= (1/2) - (-1/3)

= (3 + 2)/6

= 5/6

Now,

Subtract -71/36 from 5/6

= (5/6) - (-71/36)

= 5/6 + 71/36

= (30 + 71)/36

= 101/36

Answer :

101/36