Question

subtract the sum of 2a + 3b , a - 2b + c , -a + 2c and 4a + 2b - 8 from 10a - 10b + 3​

Answer 1

Step-by-step explanation:

first we 10a-10b+3 subtract 4a+2a-8

6a-8b+5

Answer 2

$\large\sf\underline{Understanding\:the\:question:}$

Firstly we need to add (2a + 3b) , (a - 2b + c) , (-a+2c) and (4a + 2b - 8) . Then the sum of all these expression must be subtracted from (10a - 10b + 3) . I will solve this question in two steps. So let's begin !

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$\large\sf\underline{Solution:}$

$\dag\:\underline{\sf 1^{st}\:step:}$

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• Let's add :

$\sf\to\:(2a + 3b)+(a - 2b + c)+(-a+2c)+(4a + 2b - 8)$

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• Opening the brackets

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$\sf\to\:2a + 3b+a - 2b + c-a+2c+4a + 2b - 8$

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• Pairing like terms together

$\sf\to\:2a+a-a+4a+ 3b- 2b+ 2b + c+2c - 8$

$\sf\to\:2a+4a+a-a+ 3b- 2b+ 2b + c+2c - 8$

$\sf\to\:6a+\cancel{a}-\cancel{a}+ b+ 2b + 3c - 8$

$\large{\mathfrak\purple{\to\:6a+3b+3c-8}}$

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$\dag\:\underline{\sf 2^{nd}\:step:}$

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• Let's subtract the sum we got with (10a - 10b +3)

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Subtracting (6a - 3b + 3c - 8) from (10a - 10b + 3)

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$\sf\to\: (10a - 10b + 3)- (6a - 3b + 3c - 8)$

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• Opening the brackets

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$\sf\to\: 10a - 10b + 3- 6a + 3b - 3c + 8$

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• Pairing like terms together

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$\sf\to\: 10a- 6a- 10b+ 3b- 3c+ 3+ 8$

$\large{\mathfrak\purple{\to\:4a-7b-3c+11}}$

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!! Hope it helps !!