subtract the sum of 2a+3b,a-2b+c,-a+2cand 4a+2b-5 from 6a-44b+8
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Answer:
48b+3c-13=0
Step-by-step explanation:
2a+3b
a-2b+c
-a+2c
4a+2b-5
total is 6a+4b+3c-5
subract it from 6a-44b+8
Therefore 6a+4b+3c-5-(6a-44b+8)=0
6a+4b+3c-5-6a+44b-8=0
48b+3c-13=0
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