Question

Subtract the sum of 3a + 3b, 2a-2b+c, -a +2c and 4a + 3b-5 from 7a-4b +8​

Answer 1

We need to subtract the sum of 2a + 3b, a - 2b + c, - a + 2c and 4a + 2b - 5 from 6a - 4b + 8.

Sum of 2a + 3b, a - 2b + c, - a + 2c and 4a + 2b - 5 is

(2a+3b)+(a-2b+c)+(-a+2c)+(4a+2b-5)(2a+3b)+(a−2b+c)+(−a+2c)+(4a+2b−5)

Combine like terms.

(2a+a-a+4a)+(3b-2b+2b)+(c+2c)-5(2a+a−a+4a)+(3b−2b+2b)+(c+2c)−5

6a+3b+3c-56a+3b+3c−5

Subtract 6a+3b+3c-5 from 6a - 4b + 8.

(6a-4b+8)-(6a+3b+3c-5)(6a−4b+8)−(6a+3b+3c−5)

6a-4b+8-6a-3b-3c+56a−4b+8−6a−3b−3c+5

On combining like terms we get

(6a-6a)+(-4b-3b)+(-3c)+(8+5)(6a−6a)+(−4b−3b)+(−3c)+(8+5)

-7b-3c+13−7b−3c+13

Therefore, the required expression -7b-3c+13.

hope it helps you dear:) have a great day ahead

Answer 2

Step-by-step explanation:

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