Question

subtract the sum of 3p -2q + 2r, 5p+ 3q -2r and -4p+ 2q -3r from the sum of 2p-3q -3r , 4p-q-r and 3p-2q-3r​

Answer 1

first we do the sum

(2p-3q-3r)+(-4p-q-r)+(3p-2q-3r)

2p-3q-3r-4p-q-r+3p-2q-3r

2p-4p+3p-3q-q-2q-3r-r-3r

(2-4+3)p+(-3-1-2)q+(-3-1-3)r

p-6q-7r

(3p-2q+2r)+(5p+3q-2r)+(-4p+2q-3r)

3p-2q+2r+5p+3q+2r-4p+2q-3r

3p+5p-4p-2q+3q+2q+2r+2r-3r

(3+5-4)p+(-4-2+3)q+(2r+2r-3r)

4p-3q+r

subtracting sum A from sum B

(p-6q-7r)-(4p-3q+r)

p-6q-7r-4p+3q-r

p-4p-6q+3q-7r-r

(1-4)p+(-6+3)q+(-7-1)r

-3p+-3q-8r

Answer 2

Answer:

I hope answer is helpful to us