Question

Subtract the sum of 4 x square + 3 X Y + 2 y square and 3 x square - 3 x y from the sum of 3 x square - 7 x y and 2 x square - 8 x y + 4 y square

Answer 1

Answer:

$2x^2+2y^2+15xy$

Step-by-step explanation:

$(4x^2+3xy-2y^2 )+(3x^2-3xy)\\=7x^2-2y^2$

$(3x^2-7xy )+(2x^2-8xy-4y^2)\\=5x^2-15xy-4y^2$

$=(7x^2-2y^2)-(5x^2-15xy-4y^2)\\=7x^2-5x^2-2y^2+4y^2+15xy\\=2x^2+2y^2+15xy$