Math, asked by Susamarani, 4 months ago

Subtract the sum of 4a-b+3c and 2a+4b-c from -7a+3b+8c

Answers

Answered by kamalrajatjoshi94

1

Answer:

-7a+3b+8c-(4a-b+3c+2a+4b-c)

-7a+3b+8c-(6a+3b+2c)

-7a+3b+8c-6a-3b-2c

-13a+6c

Answered by hannu15102006

0

Answer:

-13a+6b+6c

Step-by-step explanation:

Sum = 4a-b+3c + 2a+4b-c

= 6a-3b+2c

Difference = -7a+3b+8c - (6a-3b+2c)

= -7a+3b+8c-6a+3b-2c

=-13a+6b+6c

Hope it helps you buddy

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