Question

Subtract the sum of 5y² + y -3 and y² -3y +7 from 6y² +y -2

Answer 1

Answer:

Step-by-step explanation:

The sum of 5y² + y - 3 and y² - 3y + 7

5y² + y - 3 + y² - 3y + 7

= ( 5y² + y² ) + ( y - 3y ) + ( - 3 + 7 ) (∵ like terms adding )

= 6y² + ( - 2y ) + 4

= 6y² - 2y + 4 ( ∵ + × - = - )

Now subtracting 6y² - 2y + 4 from 6y² + y - 2

6y² - 2y + 4 - ( 6y² + y - 2 )

= 6y² - 2y + 4 - 6y² - y + 2 ( ∵ - × + = - ; - × - = + )

= ( 6y² - 6y² ) + ( - 2y - y ) + ( 4 + 2 ) ( ∵ like terms adding )

= 0 + ( - 3y ) + 6

= - 3y + 6 is the answer. ( ∵ + × - = - )