subtract the sum of 6x - 6z +3x and 7z- 4y + 13x from the sum of 2x - 7 +4y and 6x - 4z-4y
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Step-by-step explanation:
[( 2x - 7 + 4y ) + ( 6x - 4z - 4y) ] - [ ( 6x - 6z + 3x ) + (7z - 4y + 13x ) ]
= [ 8x - 4z- 7 ] - [ 22x + 1 z - 4y]
= - 14 x - 3z - 4y - 7
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