Question

Subtract the sum of (7pq - 3qr + 4rs) and (9qr + 3rs - 5pq) from the sum of (29r - 4rs + 6pq) and (11pq-3qr+5rs)
ANSWER IS ==15pq-7qr-6rs
please solve it​

Answer 1

Answer:

According to question,

−15pq,12pq,−23pq,7pq

Adding terms,

−15p+12pq−23pq+7pq

−19pq

Step-by-step explanation:

I hope this helps you dear

Answer 2

Question:-

Subtract the sum of (7pq - 3qr + 4rs) and (9qr + 3rs - 5pg) from the sum of (29r - 4rs + 6pg) and

(11pq-3qr+5rs)

Answer:-

Sum of (7pq - 3qr + 4rs) and (9qr + 3rs - 5pq) :-

(7pq - 3qr + 4rs) + (9qr + 3rs 5pq)

➞ 7pq - 3qr + 4rs +9qr + 3rs 5pq

➞ 7pq - 5pq + 9gr - 3gr + 4rs + 3rs

➞ 2pq +6qr + 7rs

Sum of (29qr - 4rs + 6pg) and (11pq-3qr+5rs) :- (29gr - 4rs + 6pq) + (11pq-3qr+5rs)

➞ 29gr - 4rs + 6pq + 11pq - 3gr + 5rs

➞ 29qr - 3qr + 5rs - 4rs + 6pq + 11pq

➞ 26qr + rs + 17pq

Subtracting their sum :-

["From" number comes first. ]

[ Original signs are changed to opposite sign while removing the bracket if there is minus sign

before the bracket ]

➞ (26qr + rs + 17pq) - (2pq + 6qr + 7rs)

➞ 26qr + rs + 17pq - 2pq - 6qr 7rs

➞ 26qr - 6qr - 7rs + rs + 17pq - 2pq

➞ 20qr - 6rs + 15pq

Ans. 20qr - 6rs + 15pq