Math, asked by shahanasajan, 2 months ago

SUBTRACT THE SUM OF 8/9 AND 1/3 FROM 12

Answers

Answered by Himsuta
0

Answer:

 \frac{97}{9}

Step-by-step explanation:

12 - ( \frac{8}{9}  +  \frac{1}{3} )

12 - ( \frac{8 + 3}{9} )

12 -  \frac{11}{9}

 \frac{108 - 11}{9}

 \frac{97}{7}

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Answered by shahegulafroz
0

Given information,

SUBTRACT THE SUM OF 8/9 AND 1/3 FROM 12

To find -

The value of SUBTRACT THE SUM OF 8/9 AND 1/3 FROM 12

Solution :-

we can write given information as,

 \frac{8}{9}  +  \frac{1}{3}  - 12

In substraction or addition of rational number the denominator of the number should be same.

Multiply 1/3 by 3/3 we get

 \frac{8}{9}  +  \frac{3}{9}  - 12

=

 \frac{8 + 3}{9}  - 12

=

 \frac{11}{9}  - 12

Multiply 12 by 9/9 we get

 \frac{11}{9}  -  \frac{108}{9}

=

 \frac{11 - 108}{9}

=

 \frac{97}{9}

Divide 97 by 9 we get

=

10.63

(In decimal)

Hence ,

The value of SUBTRACT THE SUM OF 8/9 AND 1/3 FROM 12 is 97/9 .

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