Question

Subtract the sum of 8b2 – 4c2 and 3b2 + 4c2 - 3bc from the sum of 8b2 - 3c2 and c2 + 2bc - 2b.

Answer 1

Answer:

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Answer 2

Answer:

According to the question,

{(2b

2

−2bc−c

2

)+(c

2

+2bc−b

2

)}−{(9b

2

+3c

2

)+(2b

2

+bc+2c

2

)}

={(2b

2

−b

2

)+(−2bc+2bc)+(c

2

−c

2

)}−{(9b

2

+2b

2

)+(3c

2

+2c

2

)+bc}

=(b

2

)−(11b

2

+5c

2

+bc)

=b

2

−11b

2

−5c

2

−bc

=−10b

2

−bc−5c

2

.