Question

subtract the sum of ( 8m -7n +6p^2 )and (-3m -4n -p^2 ) from the sum of ( 2m +4n -3p^2 ) and (-m -n -p^2 )

Answer 1

$\underline{\Large\mathbf{Question}}$

Subtract the sum of $\bf 8m - 7n + 6{p}^{2}$ and $\bf - 3m - 4n - {p}^{2}$ from the sum of $\bf 2m + 4n - 3{p}^{2}$ and $\bf - m - n - {p}^{2}$


$\underline{\underline{\huge\mathfrak{Solution}}}$

Let us first add the equations,

Sum of $\bf 8m - 7n + 6{p}^{2}$ and $\bf - 3m - 4n - {p}^{2}$

$(8m - 7n + 6 {p}^{2} ) + ( - 3m - 4n - {p}^{2} ) \\ \\ = 8m - 7n - 6 {p}^{2} - 3m - 4n - {p}^{2} \\ \\ = 8m - 3m - 7n - 4n - 6 {p}^{2} - {p}^{2} \\ \\ \bf = 5m - 11n - 7 {p}^{2}$

Sum of $\bf 2m + 4n - 3{p}^{2}$ and $\bf - m - n - {p}^{2}$

$(2m + 4n - 3 {p}^{2} ) + ( - m - n - {p}^{2} ) \\ \\ = 2m + 4n - 3 {p}^{2} - m - n - {p}^{2} \\ \\ = 2m - m + 4n - n - 3 {p}^{2} - {p}^{2} \\ \\ \bf = m + 3n - 4{p}^{2}$

Now,

Subtracting $\bf 5m - 11n - 7{p}^{2}$ from $\bf m + 3n - 4{p}^{2}$

$(m + 3n - 4 {p}^{2} ) - (5m - 11n - 7 {p}^{2} ) \\ \\ m + 3n - 4 {p}^{2} - 5m + 11n + 7 {p}^{2} \\ \\ m - 5m + 3n + 11n - 4 {p}^{2} + 7 {p}^{2} \\ \\ \bf - 4m + 14n + 3 {p}^{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: or \\ \bf 3 {p}^{2} - 4m + 14n$

If any doubt, please ask! ;)

Answer 2

Answer:

dear shin chan001 isnt 6p2 - p2 5p2 why have u written 7p2

Step-by-step explanation: