subtract the sum of 9b²-3c²and 2b²+bc-2c² from the sum of 2b²-2bc-c² and c²+2bc-b²
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Here's your answer!
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{(2b²-2bc-c²)+(c²+2bc-b²)} -{(9b²-3c²)+(2b²+bc-2c²)}
=(b²+0+0)-(11b²+bc-5c²)
=b²-11b²-bc+5c²
=5c²-bc-10b² (Ans.)
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Here's your answer!
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{(2b²-2bc-c²)+(c²+2bc-b²)} -{(9b²-3c²)+(2b²+bc-2c²)}
=(b²+0+0)-(11b²+bc-5c²)
=b²-11b²-bc+5c²
=5c²-bc-10b² (Ans.)
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Thank you.
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