Question

subtract the sum of
$\frac{ - 36}{11} and \frac{49}{22}$
form the sum of
$\frac{33}{8} and \frac{ - 19}{4}$

Answer 1

sum of -36÷11 and 49÷22 from sum of 33÷8 and -19÷4to be subtracted
-36÷11+49÷22=-23÷22
33÷8+-19÷4 =-5÷8
thus -23÷22-(-5÷8)
=-99÷88

Answer 2

hello friend
here is your answer

subtract the sum {33/8+(-19)/4} -{(-36)/11 + 49/22}
LCM of 8 and 4 is 8
then 33/8+(-38)/8= -5/8
LCM of 11 and 22 is 2
then -72/22+ 49/22= -23/22

then (-5)/8-(-23)/22
LCM of 8 and 22 is 88
then -55/88+92/88=37/88

hope it would help you
thanks dear