Math, asked by BishBeBack4346, 1 year ago

Subtract the sum of x²–5xy+2y² and y²–2xy–3x² from the sum of 6x²–8xy–y² and 2xy–2y²–x².

Answers

Answered by amitnrw
32

Answer:

7x² - 6y²+ 6xy

Step-by-step explanation:

Subtract the sum of x²–5xy+2y² and y²–2xy–3x² from the sum of 6x²–8xy–y² and 2xy–2y²–x²

A = sum of x²–5xy+2y² and y²–2xy–3x²

B = sum of 6x²–8xy–y² and 2xy–2y²–x²

we need to find

S = B - A

B = 6x²–8xy–y²  + 2xy–2y²–x²

=> B = 5x² - 3y²- 6xy

A = x²–5xy+2y² + y²–2xy–3x²

=> A = -2x²–7xy+3y²

S = B - A

=> S = 5x² - 3y²- 6xy - (-2x²–7xy+3y²)

=> S = 5x² - 3y²- 6xy + 2x²+7xy-3y²

=> S = 7x² - 6y²+ 6xy

Answered by MARRISEporley16
1

Answer:

I dunnow sorry

Step-by-step explanation:

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