Question

The sum of 3 expressions is 8+13a+7a². Two of them are 2a²+3a+2 and 3a²–4a+1. Find the third expression.

Answer 1

In the attachment I have answered this problem.

The third expression is found by subtracting the sum of the given two expressions from RHS expression.

I hope this answer helps you

Answer 2

x=2a2+14a+5

Step-by-step explanation:

Expression be x

x+(2a2+3a+2)+(3a2-4a+1)

8+13a+7a2

=x+5a2-a+3=8+13a+7a2

x=7a2+13a+8-5a2+a-3

x=2a2+14a+5