The sum of 3 expressions is 8+13a+7a². Two of them are 2a²+3a+2 and 3a²–4a+1. Find the third expression.
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Answered by
66
In the attachment I have answered this problem.
The third expression is found by subtracting the sum of the given two expressions from RHS expression.
I hope this answer helps you
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Answered by
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x=2a2+14a+5
Step-by-step explanation:
Expression be x
x+(2a2+3a+2)+(3a2-4a+1)
8+13a+7a2
=x+5a2-a+3=8+13a+7a2
x=7a2+13a+8-5a2+a-3
x=2a2+14a+5
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