Question

Subtract x^3 - 4x - 1 from 3x^3 - x^2 + 6​

Answer 1

Answer:

$3 {x}^{3} - {x}^{2} + 6 - ( {x}^{3} + 4x - 1) \\ = 3 {x}^{3} - {x}^{2} + 6 - {x}^{3} - 4x + 1 \\ = 2 {x}^{3} - {x}^{2} - 4x + 7$

Answer 2

Answer:

$2x^{3}-x^{2} +4x+7$

Step-by-step explanation:

$(3x^{3}-x^{2}+6 )-(x^{3}-4x-1 )\\=>3x^{3}-x^{2}+6 -x^{3}+4x+1 \\=>2x^{3}-x^{2} +4x+7$