Math, asked by dg262006, 5 months ago


Subtract x2 - x – 11 from the sum of 3x2 - 8x + 11, -2x2 + 12x and −4x2

+ 7.

Answers

Answered by Yuseong
8

 {\underline {\underline {\huge {\rm { Required \: Answer: } }}}}

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Finding the sum of 3x² - 8x + 11, -2x² + 12x ans -4x² + 7.

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 \sf { ⇢ 3 {x}^{2} - 8x + 11+( -2 {x}^{2} +12x) +( -4 {x}^{2} + 7) }

(Putting the '+' at the place of comma.)

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 \sf { ⇢ 3 {x}^{2} - 8x + 11 -2 {x}^{2} +12x -4 {x}^{2} + 7 }

(Removing bracket)

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 \sf { ⇢ 3 {x}^{2} -2 {x}^{2}-4 {x}^{2}  - 8x+12x + 11 + 7 }

(Collecting all the like terms.)

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 \sf { ⇢ {x}^{2}-4 {x}^{2}  -4x + 18 }

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 \boxed { \sf \pink{ ⇢ -3 {x}^{2} -4x + 18 } }

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Now, subtracting x² - x - 11 from the sum of 3x² - 8x + 11, -2x² + 12x and -4x².

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  \sf { ⇢ -3 {x}^{2} -4x + 18 - ( {x}^{2} -x-11) }

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  \sf { ⇢ -3 {x}^{2} -4x + 18  -{x}^{2} +x+11 }

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  \sf { ⇢ -3 {x}^{2} -{x}^{2} - 4x +x + 18 +11 }

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 \boxed {  \sf \red  { ⇢ -4{x}^{2} - 3x + 29 }}

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Answer :–

  •  \boxed {  \sf \pink  { -4{x}^{2} - 3x + 29 }}

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