Succinic acid has the formula (ch2)n(cooh)2 and reacts with dilute sodium hydroxide as follows: (ch2)n(cooh)2 + 2naoh (ch2)n(coona)2 + 2h2o 2.0 g of succinic acid were dissolved in water and the solution made up to 250 cm3. this solution was placed in a burette and 18.4 cm3 was required to neutralise 25 cm3 of 0.1 moldm-3 naoh. deduce the molecular formula of the acid and hence the value of n.
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(CH2)n(COOH)2 + 2NaOH = (CH2)n(COONa)2 + 2H2O
Mole ratio: Acid : Base = 1:2
(ma x va) / (mb x vb) = 1/2
(ma x 18.4)/(0.1 x 25) = 1/2
ma = (0.1 x 25)/ (2 x 18.4)
= 0.068 M
2.0 g of succinic acid were dissolved in water and the solution made up to 250 cm³.
⇒ 250cm³ of the solution contain 2g of the acid
Mass in 1 litre = 1000/250 x 2 = 8g
Mass = molarity x molar mass
8 = 0.068 x molar mass
Molar mass = 8/0.068 = 117.76
(CH2)n(COOH)2 = 117.76
(12 + 2)n + 2(12 + 16x2 + 1) = 117.76
14n + 90 = 117.76
14n = 27.76
n = 2
The value of n = 2
the molecular formula of the acid is (CH2)2(COOH)2
Mole ratio: Acid : Base = 1:2
(ma x va) / (mb x vb) = 1/2
(ma x 18.4)/(0.1 x 25) = 1/2
ma = (0.1 x 25)/ (2 x 18.4)
= 0.068 M
2.0 g of succinic acid were dissolved in water and the solution made up to 250 cm³.
⇒ 250cm³ of the solution contain 2g of the acid
Mass in 1 litre = 1000/250 x 2 = 8g
Mass = molarity x molar mass
8 = 0.068 x molar mass
Molar mass = 8/0.068 = 117.76
(CH2)n(COOH)2 = 117.76
(12 + 2)n + 2(12 + 16x2 + 1) = 117.76
14n + 90 = 117.76
14n = 27.76
n = 2
The value of n = 2
the molecular formula of the acid is (CH2)2(COOH)2
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Answer:
n: 2
Explanation:
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