Question

Sudesh is twice as old as seema . if six years is subtracted fromseema age and four years are added to sudesh age sudesh will be four times seema age how old were they three year ago

Answer 1

Let Seema's age be x
Sudesh's age = 2x
Seema's new age = x-6
Sudesh's new age = 2x+4
A/Q 2x+4 = 4(x-6)
2x+4 = 4x-24
2x=28
x=14
Seema's age = x = 14
Sudesh's age 2x = 2x14 = 28
∴ Seema's age 3 years ago = 14-3 = 11 yrs
Sudesh's age = 28-3 = 25 yrs

Answer 2

Answer:

Let the age of Seema be x years.

Therefore, age of Sudesh will be 2x years.

It is given that, If six years is subtracted from Reha's age and four years added to Ishita's age :]

Age of Seema = x - 6

Age of Sudesh = 2x + 4

According to Question now,

➳ 4(x - 6) = 2x + 4

➳ 4x - 24 = 2x + 4

➳ 4x - 2x = 4 + 24

➳ 2x = 28

➳ x = 28/2

➳ x = 14 years

Therefore,

Present age of Seema = x = 14 years

Present age of Sudesh = 2x = 2(14) = 28 years

So,

• Age of Seema 3 years ago = x - 3 = 14 - 3 = 11 years.

• Age of Sudesh 3 years ago = 2x - 3 = 28 - 3 = 25 years.