Math, asked by npathak8933, 11 months ago

Sudesh is twice as old as seema.if six years is subtracted from seema 'age and 4 years are added to sudesh'age,sudesh will be 4 times seema's age .how old were they three years ago?

Answers

Answered by Brendancrawford
1

Answer:


Step-by-step explanation:

let present age of seema = x yrs

sudesh = 2x yrs

4( x-6) = 2x + 4

4x - 24 = 2x +4

4x - 2x=4+24

2x = 28

x=14

present age of seema=14 yrs

present age of sudesh= 28 yrs

3 yrs ago age of seema = 11 yrs

3 yrs ago age of sudesh =25 yrs

seema was 11 yrs old and sudesh was 25 yrs old 3 yrs ago


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Answered by anwesha2672
1

Answer:

Seema’s age=11

Sudesh’s age =25

Step-by-step explanation:

Explanation in attachment

Please mark my answer as brainliest

Attachments:
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