Question

Sudha is twice as old as her brother. three years ago sudha age was three times of her brother age. find the age of sudha

Answer 1

$\large{\boxed{\bold{Answer:}}}$


Let the age of Sudha's brother be x

Sudha's age = 2x


Their ages three years ago,

$Sudha = (2x - 3) \\ \\ Sudha's brother = (x - 3)$

Now,

$2x - 3 = 3(x - 3) \\ \\ = > 2x - 3 = 3x - 9 \\ \\ = > x = 6$

Sudha's age = 2x = 2×6 = 12 years


$\large{\boxed{\bold{Hope\:it\:helps\:you!}}}$

Answer 2

$Heya Mate$

$<b>Here Is U Are Solution$

Let sudha's brother age be x.

sudha age=2x.

3 yrs ago
Sudha age=2x-3

his brother age=3(x-3)

=2x-3=3x-9

2x-3x=-9-3

x=12

Hope This Will Help u!!!!

$Be\: Happy\:Be\:Brainly$