Question

Sudhir and Deepak start from point A to walk over a rectangular park. Sudhir walks Directly
from A to D to C while Deepak walks directly from A to C. How much more does
Deepak walk than Sudhir?

Answer 1

Answer:

Dist. travelled by Sudhir=AD+DC=70m+24m=94m

Dist. travelled by Deepak

$= \sqrt{ad {}^{2} + dc {}^{2} } \: (by \: pythgoras \: th.) \\ = \sqrt{70 {}^{2} + 24 {}^{2} } \\ = \sqrt{4900 + 576} \\ = \sqrt{5476 } \\ = 74m$

Difference of dist. travelled=94m-74m=20m

Sudhir walks 20m more than Deepak

Answer 2

Answer:

Sudhir walked 20 meter more than Deepak.

Step-by-step explanation:

Sudhir starts from point A to point D to point C.

Total distance walked by Sudhir = 70 m + 24 m = 94 meter

Deepak walks directly from A to C that is diagonal of a rectangle.

So we use the formula to solve for diagonal of a rectangle :

$d=\sqrt{w^2+L^2}$

$d=\sqrt{24^2+70^2}$

d = 74 meter

Deepak walked 74 meter.

Difference between the distance walked by sudhir and Deepak

= 94 - 74 = 20 meter

Sudhir walked 20 meter more than Deepak.

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