Math, asked by srisaiagencies1774, 10 months ago

Sudhir borrowed rupees 16000 from Ashok at 10% simple interest for 3by2 years after 2 years sushi was to clear to dept Ashok insisted Sudhir to pay him compound interest compounded half yearly how much more must sudhir pay

Answers

Answered by amitnrw

Step-by-step explanation:

Taking two case 3/2 Years and 2 Years

P = 16000

R = 10 % compounded half yearly

n = 3/2 or 2

n = 3/2

Compound interest = 16000 (1 + 10/200)³ - 16000 = 2522

Simple interest = 16000 * 10 * (3/2)/100 = 2400

Extra interest to pay in 3/2 years = 2522 - 2400 = Rs 122

n = 2

Compound interest = 16000 (1 + 10/200)⁴ - 16000 = 3448.1

Simple interest = 16000 * 10 * 2/100 = 3200

Extra interest to pay in 3/2 years = 3448.1 - 3200 = Rs 248.1

Sudhir has to pay RS 122 Extra in 3/2 years & Rs 248.1 in 2 Years

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Answered by kundankumarray9398

Step-by-step explanation:

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