Question

Sudhir has the habit of collecting coins of rs 1,rs 5 and rs 10,he has these denominations in the ratio of 2:3:4.ONE day he counts the money ans found he has the collection the rs 741.find the number of coins of each denomination

Answer 1

Let the coin of ₹1 be 2x
The coin of ₹5 be 3x
The coin of ₹10 be 4x
So, the rupees of coin of 1 = 2x
the rupees of coin of 5= 15x
the rupees of coin of 10=40x
According to the question
Total rupees Sudhir have =741
So,
$2x + 15x + 40x = 741$
so,
$x = 13$
so,
the coin of ₹1= 2x

$2 \times 13 = 26$
The coin of ₹5= 3x
$5 \times 13 = 65$
The coin of ₹10 = 4x
$4 \times 13 = 52$

Answer 2

Answer:

Let the number of Rs.1, Rs.5 and Rs.10 coins be 2x, 3x and 4x respectively.

Value of Rs.1 coins is :

$1 \times 2x = 2x$

Value of Rs.5 coins is:

$5 \times 3x = 15x$

Value of Rs.10 coins is:

$10 \times 4x = 40x$

Total money he has = Rs.741

A/Q,

$2x + 15x + 40x = 741 \\ = > 57x = 741 \\ = > x = \frac{741}{57} = 13$

Hence, Number of Rs.1 coins is 2 x 13=26

Number of Rs.5 coins is 3 x 13= 39

Number of Rs.10 coins is 4 x 13=52

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