sugar content 30 gram of sugar dissolved in 370 gram of water calculate concentration of the solutionwhat is solubility 12 gram of Potassium Sulphate dissolved in 75 gram of water at 60 degree Celsius what is the solubility in water at this temperature
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A solution contains a solid solute (sugar ) dissolved in a liquid solvent (water),so we have to calculate the concentration of this solution in terms of the mass percentage of solute (sugar ) we, Know that : <br> Concentration of solution
<br> here, Mass of solute (sugar )=30g <br> And ,Mass of solvent (water)=370g <br> So ,Mass of solution = Mass of solute + Mass of solvent <br> =30+370 <br> =400 g <br> Now ,Putting the values Of mass of solute and mass of solution in the above formula formula ,WE get : <br> Concentration of solution
<br>
<br> 7.5 per cent (or 7.5% ) <br> THus , the concentration of this sugar solution is 7.5 per cent (or that it is a 7.5 % sugar solution).
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TheUrvashi
TheUrvashi
01.06.2018
Science
Secondary School
+5 pts
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Hey Dear users⤵⤵⤵⤵
Question:12 grams of Potassium Sulphate dissolves in 75 grams of water at 60 degree celsius .what is the solubility in water at that temperature??
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Gaurav249
Gaurav249 Genius
Hii Mate___☺
here's your answer___⤵
☆it is given that 75 g of water dissolves 12 g of
potassium sulphate
___
75g of water dissolved = 12g of potassium sulphate ,
So, 100g of water will dissolve =
12/75 × 100 g of potassium sulphate .= 16 g of potassium sulphate .
thus,the solubility of potassium sulphate in water is 16 g at 60°c.
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Explanation:
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