Math, asked by adithyansivadas868, 19 days ago

Suhas sold two paintings for ₹99,000 each. On one he incurred a loss of 10% and on the other he gained by 10%. Find his actual gain or loss percent on the transaction.​

Answers

Answered by natyavidhanbiswas10
3

SP of both paintings= ₹99000

 

For the first painting, he gains 10%  

Thus CP = [SP/(100 + gain %)] × 100  

=> CP = [99000/(100+10)] × 100  

=> CP = ₹ 90000  

For the second painting, he loses 10%

Thus CP = [SP/(100 - loss %)] × 100

=> CP = [99000/(100-10)] × 100

=> CP = ₹ 110000

 

Total Cost price = 110000+90000 = ₹200000

Total selling price = 99000×2 = ₹198000

Total loss = 200000-198000 = ₹2000

loss % = 2000/200000 × 100 = 1 %

Thus, he loses 1% in the whole transaction.

Answered by ItzAvni
1

Answer:

The first painting, he gains 10%

Thus CP= [SP/( 100 + gain % ) ] × 100

-> CP = [ 99000/ ( 100 + 10 ) ] × 100

-> CP = 90000

The second painting, he loses 10%

Thus CP = [ SP/( 100 - loss % ) ]

-> CP = [ 99000 /( 100 - 10 )] × 100

-> CP = 110000

Total Cost Price = 110000 + 90000 = 200000

Total Selling Price = 99000 × 2 = 198000

Total Lost = 200000 - 198000 = 2000

Loss % = 2000/200000 × 100 = 1%

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