Question

suitable example,
Write the molecular orbital configuration of
carbon monoxide. Calculate its bond order.​

Answer 1

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Species CO (14), contain bonding electrons=10 and antibonding electrons =4.

$\huge \bf\frac{N_b - N_a}{2} = \frac{10 - 4}{2} = 3$

Carbon dioxide is electron-poor at the central carbon and acts as an electrophile. The molecular orbital diagram of carbon monoxide is very similar to that of molecular nitrogen. Carbon, with 4 valence electrons, and oxygen with 6 valence electrons, together have the same number of electrons as dinitrogen.

The suggested molecular orbital electronic configuration of Co is : KK(σ2s)2(σ2s)2,(π2px)2(π2py)2(σ2pz)2.

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