Question

sukanta is 6 times older than his brother. The sum of their ages is 28 years. Find the age of sukanta and his brother ​

Answer 1

Answer: let his brother's age be 'y'

Shakuntala's age = 6 times of y = 6y

Sum of their ages = 28

Therefore, 6y+y=28

7y=28

y= 28/7 = 4

His brother's age will be 4 years

Her is six times of her brother so it will be 6*4 = 24 years

You can also verify as 24+4=28

Step-by-step explanation:

Answer 2

Answer:4 and 24

Explanation:

Let sukantabrother's age be x

then sukanta age be 6x

A/q

6x+x=28

7x=28

x=4

Age of sukanta's brother=4 year

Sukanta's age=6x

=6×4=24 year