Sulphur dioxide occupies a volume of 512 cm3 at STP. Find its volume at 27C and at a pressure of 720 mm of mercury.
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Answered by
22
V1 = 512cm3
P1 = 760mm of Hg
T1 = 273 kelvin or K
V2 = ?
P2 = 720mmof Hg
T2 = (27+273)K = 300K
we know ,
P1 V1/T1. = P2 V2/T2
therefore,
V2 = P1 V1/TI. × T2/P2
= 760×512/273 × 300/720
= 593.894 cm3
or 594 cm3 (approx)
Hope this helps......
P1 = 760mm of Hg
T1 = 273 kelvin or K
V2 = ?
P2 = 720mmof Hg
T2 = (27+273)K = 300K
we know ,
P1 V1/T1. = P2 V2/T2
therefore,
V2 = P1 V1/TI. × T2/P2
= 760×512/273 × 300/720
= 593.894 cm3
or 594 cm3 (approx)
Hope this helps......
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5
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