Question

sulphur exists in three different allotropic forms like S2,S6,S8 etc.,If equal weight of three are taken in seperate container , then the ratio of number of atoms is
1)1:3:4
2)2:4:3
3)1:1:1
4)1:1:4

Answer 1

the ratio of sulphur is 3)1:1:1

Answer 2

Answer: The ratio of number of atoms is 1:3:4

Explanation:

Number of moles = $\frac{w}{\text{molar mass}}$

Molar mass of $S_2=2\times \text{molar mass of sulfur}=2\times 32.07$

Molar mass of $S_6=6\times \text{molar mass of sulfur}=6\times 32.07$

Molar mass of $S_8=8\times \text{molar mass of sulfur}=8\times 32.07$

Moles of $S_2=\frac{w}{2\times 32.07}$

Moles of $S_6=\frac{w}{6\times 32.07}$

Moles of $S_8=\frac{w}{8\times 32.07}$

Number of atoms : moles × $N_A$

The ratio of number of atoms is:

Number of atoms $S_2:S_6:S_8$

$\frac{w}{2\times 32.07}N_A:\frac{w}{6\times 32.07}N_A\frac{w}{8\times 32.07}N_A=1:3:4$

The ratio of number of atoms is 1:3:4