Sulphuric acid is not used during reaction of alcohols with KI.give reason..
Answers
In the presence of sulphuric acid (H2SO4), KI produces HI
In the presence of sulphuric acid (H2SO4), KI produces HI2KI + H2SO4 → 2KHSO4 + 2HI
In the presence of sulphuric acid (H2SO4), KI produces HI2KI + H2SO4 → 2KHSO4 + 2HISince H2SO4 is an oxidizing agent, it oxidizes HI (produced in the reaction to I2).
In the presence of sulphuric acid (H2SO4), KI produces HI2KI + H2SO4 → 2KHSO4 + 2HISince H2SO4 is an oxidizing agent, it oxidizes HI (produced in the reaction to I2).2HI + H2SO4 → I2 + SO2 + H2O
In the presence of sulphuric acid (H2SO4), KI produces HI2KI + H2SO4 → 2KHSO4 + 2HISince H2SO4 is an oxidizing agent, it oxidizes HI (produced in the reaction to I2).2HI + H2SO4 → I2 + SO2 + H2OAs a result, the reaction between alcohol and HI to produce alkyl iodide cannot occur. Therefore, sulphuric acid is not used during the reaction of alcohols with KI. Instead, a non-oxidizing acid such as H3PO4 is used.
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